# scipy.ndimage.find_objects

scipy.ndimage.find_objects(input, max_label=0)

  Find objects in a labeled array.

  Parameters:
    input ndarray of ints

      Array containing objects defined by different labels. Labels with value 0 are ignored.

    max_label int, optional

      Maximum label to be searched for in input. If max_label is not given, the positions of all objects are returned.

  Returns:
    object_slices list of tuples

      A list of tuples, with each tuple containing N slices (with N the dimension of the input array). Slices correspond to the minimal parallelepiped that contains the object. If a number is missing, None is returned instead of a slice. The label `l` corresponds to the index `l-1` in the returned list.

  See also

  `label`, `center_of_mass`

  Notes

  This function is very useful for isolating a volume of interest inside a 3-D array, that cannot be “seen through”.

  Examples

      >>> from scipy import ndimage
      >>> import numpy as np
      >>> a = np.zeros((6,6), dtype=int)
      >>> a[2:4, 2:4] = 1
      >>> a[4, 4] = 1
      >>> a[:2, :3] = 2
      >>> a[0, 5] = 3
      >>> a
      array([[2, 2, 2, 0, 0, 3],
             [2, 2, 2, 0, 0, 0],
             [0, 0, 1, 1, 0, 0],
             [0, 0, 1, 1, 0, 0],
             [0, 0, 0, 0, 1, 0],
             [0, 0, 0, 0, 0, 0]])
      >>> ndimage.find_objects(a)
      [(slice(2, 5, None), slice(2, 5, None)), (slice(0, 2, None), slice(0, 3, None)), (slice(0, 1, None), slice(5, 6, None))]
      >>> ndimage.find_objects(a, max_label=2)
      [(slice(2, 5, None), slice(2, 5, None)), (slice(0, 2, None), slice(0, 3, None))]
      >>> ndimage.find_objects(a == 1, max_label=2)
      [(slice(2, 5, None), slice(2, 5, None)), None]

      >>> loc = ndimage.find_objects(a)[0]
      >>> a[loc]
      array([[1, 1, 0],
             [1, 1, 0],
             [0, 0, 1]])