# scipy.stats.mstats.count_tied_groups

scipy.stats.mstats.count_tied_groups(x, use_missing=False)

  Counts the number of tied values.

  Parameters:
    x sequence

      Sequence of data on which to counts the ties

    use_missing bool, optional

      Whether to consider missing values as tied.

  Returns:
    count_tied_groups dict

      Returns a dictionary (nb of ties: nb of groups).

  Examples

      >>> from scipy.stats import mstats
      >>> import numpy as np
      >>> z = [0, 0, 0, 2, 2, 2, 3, 3, 4, 5, 6]
      >>> mstats.count_tied_groups(z)
      {2: 1, 3: 2}

  In the above example, the ties were 0 (3x), 2 (3x) and 3 (2x).

      >>> z = np.ma.array([0, 0, 1, 2, 2, 2, 3, 3, 4, 5, 6])
      >>> mstats.count_tied_groups(z)
      {2: 2, 3: 1}
      >>> z[[1,-1]] = np.ma.masked
      >>> mstats.count_tied_groups(z, use_missing=True)
      {2: 2, 3: 1}